2022-10-14
2179
#react
Esteban Herrera
254
Oct 14, 2022 ⋅ 7 min read

Immutability in React: Should you mutate objects?

Esteban Herrera Family man. Java and JavaScript developer. Swift and VR/AR hobbyist. Like books, movies, and still trying many things. Find me at eherrera.net

Recent posts:

Implementing Infinite Scroll In React Snap Carousel

Implementing infinite scroll in React with React Snap Carousel

Making carousels can be time-consuming, but it doesn’t have to be. Learn how to use React Snap Carousel to simplify the process.

David Omotayo
Dec 13, 2024 ⋅ 10 min read
React Libraries For Building Forms And Surveys

React libraries for building forms and surveys

Consider using a React form library to mitigate the challenges of building and managing forms and surveys.

Hussain Arif
Dec 11, 2024 ⋅ 7 min read
Hoppscotch Vs Postman: A Guide To API Testing

Hoppscotch vs. Postman: a guide to open source API testing

In this article, you’ll learn how to set up Hoppscotch and which APIs to test it with. Then we’ll discuss alternatives: OpenAPI DevTools and Postman.

Chigozie Oduah
Dec 10, 2024 ⋅ 5 min read
React Native logo over red background.

Implementing camera functionality in React Native

Learn to migrate from react-native-camera to VisionCamera, manage permissions, optimize performance, and implement advanced features.

Chimezie Innocent
Dec 9, 2024 ⋅ 13 min read
View all posts

5 Replies to "Immutability in React: Should you mutate objects?"

  1. In JavaScript, strings are not arrays so you can do something like this:

    str[2] = ‘d’;

    But you cannot do this.

  2. Is there a missing “not” in this sentence: “In JavaScript, strings are not arrays so you can do something like this:

    str[2] = ‘d’;”

  3. In the above example, both references (str1 and str2) are equal because they point to the same object (‘abc’).

    I would change this phrase and also the image it is confusing… because in the end they are not pointing to the same object abc.. they have different values.. so no matter if you change str1 , str2 wont be affected. Because strings are primitive not references.. therefore there;s no pointing.

Leave a Reply